Simpson Rule
If we divide [a,b] into n equal intervals, each of width:
| The first rectangle has area | ![]() |
| The second rectangle has area | ![]() |
| The ith rectangle has area | ![]() |
| The nth rectangle has area | ![]() |
The area under f range [a,b] is therefore:

If we divide [a,b] into n equal intervals, each of width:
| The first rectangle has area | ![]() |
| The second rectangle has area | ![]() |
| The ith rectangle has area | ![]() |
| The nth rectangle has area | ![]() |
The area under f range [a,b] is therefore:
