Math Help Roots
May 15th, 2010
Question: Algebra roots Math Help please?
1.sqrt24a^3b
2.Find the principal root. sqrt16
3.sqrtX^4
4.Find the principal root. sqrt64
5.Find the principal root. sqrt8
6.sqrt16xy^2
7.sqrt9x^2y^6
8.sqrt12 multiplied by sqrt6
9.sqrt25x^2y
10.Find the principal root. sqrt3600
Answer: 1.sqrt24a^3b
-sqrt(6*4*a^2*a*b) ———->from here 4 & a^2 can take sqrt
-2asqrt(6ab)
2.Find the principal root. sqrt16
-sqrt(16) = sqrt(4*4) = 4
3.sqrtX^4 = sqrt(x^2 * x^2) = x^2
4.Find the principal root. sqrt64
-sqrt(64) = sqrt(8*8) = 8
5.Find the principal root. sqrt8
-sqrt(8) = sqrt(2*4) ——–> where sqrt 4 is 2
-2sqrt(2)
6.sqrt16xy^2
-sqrt(16xy^2) = sqrt(4 * 4 * x * y^2)
-4ysqrt(x)
7.sqrt9x^2y^6
-sqrt(9x^2y^6) = 3xy^3
8.sqrt12 multiplied by sqrt6
-sqrt(12 * 6) = sqrt(72) = sqrt(36 * 2)——–>where 36 is the sqaure of 6
-6sqrt(2)
9.sqrt25x^2y ———>where 25 is sq of 5 & x^2 is sq of x
-sqrt25x^2y = 5xsqrt(y)
10.Find the principal root. sqrt3600
-sqrt(3600) ——->where 3600 is the sq of 60
-sqrt(3600) = 60
Square Roots – YourTeacher.com – Math Help
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