Math Help Trigonometry
September 6th, 2007
Question: I need some help in Math- Trigonometry?
Really hard take home test. :/
Find the diagonal of a square whos perimeter is 12.
all i know is each side would be 3 then.
& the sides of a right triangle measure 10, 24 and 26 to the nearest degree whats the measure of the smallest angle? (can you explain how to do this?)
Answer: 1. diagonal = 3 sqrt 2
…..The triangle is a 45:45:90 or 1:1:sqrt2
…..3:3:3sqrt2
2. sin x = 10/26
…..sin x = 22.6 or 23 degrees
…..10 would be opposite the smallest angle,
…..use sin of unknown = 10/26 and solve for x.
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