Archive for December, 2006

Math Help Averages

math help averages
Question: I don’t understand average rate of change. AT ALL! (9th grade math)?

I’m taking an online class, and I don’t understand it at all. (9th grade math) Average Rate of Change is confusing. I don’t understand the concept, or how to do ANYTHING with average rate of change.

I have to turn this in my wednesday, so PLEASE HELP! She gives us video’s and a few things, but the review is not like the assignment.

How do you determine the average rate of change from a graph? How do you calculate avg. roc from a set of points or a table? How can equations be written in slope intercept form.

Answer: hi, so say for example, the avg rate of change is meters/second
your graph would be distance vs time
to get the avg rate of change, it is the same as the slope of the graph which is rise/run —> (y2-y1)/(x2-x1) which are two points
this is the same for points in a table, you find two points and calculate the slope using the formula above
I am guessing that since its grade 9 math, the line would be a straight line anyways, but pick another pair of points to make sure that the slope is constant through out when it is in a table form (if its in graph, its probably a straight line, or you construct a line of best fit?)

slope intercept form is y=mx+b
where m is the slope and b is the y=intercept
basically, to write it in y=mx+b form, you isolate for y ^^
hope this helps

Math Help : How to Calculate an Average


Binomial Expansion

Below are formulas for binomial expansion. Binomial expansion is very useful in math and can be applied to many real life situations.

For positive integers n (Positive integers)

Binomial expansion

Another useful binomial expansion is:

Binomial formula

for negative integers

Math Help Area

math help area
Question: Please Help With Math area problem?

Express the area of a rectangular field whose perimeter is 320 meters as a function of the length of one of its sides. Estimate the dimensions of the field of maximum area.

Answer: Let L = length and W = width.
2L + 2W = 320, so L = 160 – W
Area = L * W = (160 – W) * W = 160W – W^2
Set the derivative equal to zero.
160 – 2W = 0
W = 80, L = 80, Area = 6400 sq m

Surface Area – YourTeacher.com – Math Help