Math Homework Solutions
November 16th, 2006
Question: Iodine Solutions (Math Problem) HELP FAST PLZZ!!!!!! =(?
There’s one question on my math homework that I’ve been struggeling with for an hour. I know it’s easy and I know it’s below me but I can’t figure it out. Please try and take a whack at it.
Jay has 30% iodine solution and John has 50% iodine solution. The two mix their solutions to get a solution that is 800 mL total, and 45% iodine. How much of each solution went into the mix?
I keep getting that John mixes 600 mL but I don’t think that’s correct.
Oh and thanks!
Answer: I dont know how to use equations to solve it, so I’ll use common sense and reasoning.
Jay has 30% and John has 50%
The end result has 45%, so we know that John put in more than Jay.
If there is 800mL, lets say John puts in 600mL and Jay puts in 200mL.
600mL at 50% is 300mL (this is exactly how much iodine John contributes to the total)
200mL at 30% is 60mL (this is exactly how much iodine Jay contributes to the total)
So together, they have 360mL of iodine, which is 45% of 800.
So your answer of John mixing 600mL is correct.
Hope this helps!
Math Homework
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